Integrand size = 29, antiderivative size = 276 \[ \int (g+h x)^3 \log \left (e \left (f (a+b x)^p (c+d x)^q\right )^r\right ) \, dx=-\frac {(b g-a h)^3 p r x}{4 b^3}-\frac {(d g-c h)^3 q r x}{4 d^3}-\frac {(b g-a h)^2 p r (g+h x)^2}{8 b^2 h}-\frac {(d g-c h)^2 q r (g+h x)^2}{8 d^2 h}-\frac {(b g-a h) p r (g+h x)^3}{12 b h}-\frac {(d g-c h) q r (g+h x)^3}{12 d h}-\frac {p r (g+h x)^4}{16 h}-\frac {q r (g+h x)^4}{16 h}-\frac {(b g-a h)^4 p r \log (a+b x)}{4 b^4 h}-\frac {(d g-c h)^4 q r \log (c+d x)}{4 d^4 h}+\frac {(g+h x)^4 \log \left (e \left (f (a+b x)^p (c+d x)^q\right )^r\right )}{4 h} \]
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Time = 0.09 (sec) , antiderivative size = 276, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.069, Rules used = {2581, 45} \[ \int (g+h x)^3 \log \left (e \left (f (a+b x)^p (c+d x)^q\right )^r\right ) \, dx=-\frac {p r (b g-a h)^4 \log (a+b x)}{4 b^4 h}-\frac {p r x (b g-a h)^3}{4 b^3}-\frac {p r (g+h x)^2 (b g-a h)^2}{8 b^2 h}+\frac {(g+h x)^4 \log \left (e \left (f (a+b x)^p (c+d x)^q\right )^r\right )}{4 h}-\frac {p r (g+h x)^3 (b g-a h)}{12 b h}-\frac {q r (d g-c h)^4 \log (c+d x)}{4 d^4 h}-\frac {q r x (d g-c h)^3}{4 d^3}-\frac {q r (g+h x)^2 (d g-c h)^2}{8 d^2 h}-\frac {q r (g+h x)^3 (d g-c h)}{12 d h}-\frac {p r (g+h x)^4}{16 h}-\frac {q r (g+h x)^4}{16 h} \]
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Rule 45
Rule 2581
Rubi steps \begin{align*} \text {integral}& = \frac {(g+h x)^4 \log \left (e \left (f (a+b x)^p (c+d x)^q\right )^r\right )}{4 h}-\frac {(b p r) \int \frac {(g+h x)^4}{a+b x} \, dx}{4 h}-\frac {(d q r) \int \frac {(g+h x)^4}{c+d x} \, dx}{4 h} \\ & = \frac {(g+h x)^4 \log \left (e \left (f (a+b x)^p (c+d x)^q\right )^r\right )}{4 h}-\frac {(b p r) \int \left (\frac {h (b g-a h)^3}{b^4}+\frac {(b g-a h)^4}{b^4 (a+b x)}+\frac {h (b g-a h)^2 (g+h x)}{b^3}+\frac {h (b g-a h) (g+h x)^2}{b^2}+\frac {h (g+h x)^3}{b}\right ) \, dx}{4 h}-\frac {(d q r) \int \left (\frac {h (d g-c h)^3}{d^4}+\frac {(d g-c h)^4}{d^4 (c+d x)}+\frac {h (d g-c h)^2 (g+h x)}{d^3}+\frac {h (d g-c h) (g+h x)^2}{d^2}+\frac {h (g+h x)^3}{d}\right ) \, dx}{4 h} \\ & = -\frac {(b g-a h)^3 p r x}{4 b^3}-\frac {(d g-c h)^3 q r x}{4 d^3}-\frac {(b g-a h)^2 p r (g+h x)^2}{8 b^2 h}-\frac {(d g-c h)^2 q r (g+h x)^2}{8 d^2 h}-\frac {(b g-a h) p r (g+h x)^3}{12 b h}-\frac {(d g-c h) q r (g+h x)^3}{12 d h}-\frac {p r (g+h x)^4}{16 h}-\frac {q r (g+h x)^4}{16 h}-\frac {(b g-a h)^4 p r \log (a+b x)}{4 b^4 h}-\frac {(d g-c h)^4 q r \log (c+d x)}{4 d^4 h}+\frac {(g+h x)^4 \log \left (e \left (f (a+b x)^p (c+d x)^q\right )^r\right )}{4 h} \\ \end{align*}
Time = 0.18 (sec) , antiderivative size = 231, normalized size of antiderivative = 0.84 \[ \int (g+h x)^3 \log \left (e \left (f (a+b x)^p (c+d x)^q\right )^r\right ) \, dx=\frac {\frac {1}{12} r \left (-\frac {p \left (12 b h (b g-a h)^3 x+6 b^2 (b g-a h)^2 (g+h x)^2+4 b^3 (b g-a h) (g+h x)^3+3 b^4 (g+h x)^4+12 (b g-a h)^4 \log (a+b x)\right )}{b^4}-\frac {q \left (12 d h (d g-c h)^3 x+6 d^2 (d g-c h)^2 (g+h x)^2+4 d^3 (d g-c h) (g+h x)^3+3 d^4 (g+h x)^4+12 (d g-c h)^4 \log (c+d x)\right )}{d^4}\right )+(g+h x)^4 \log \left (e \left (f (a+b x)^p (c+d x)^q\right )^r\right )}{4 h} \]
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Leaf count of result is larger than twice the leaf count of optimal. \(1078\) vs. \(2(254)=508\).
Time = 291.42 (sec) , antiderivative size = 1079, normalized size of antiderivative = 3.91
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Leaf count of result is larger than twice the leaf count of optimal. 679 vs. \(2 (254) = 508\).
Time = 0.30 (sec) , antiderivative size = 679, normalized size of antiderivative = 2.46 \[ \int (g+h x)^3 \log \left (e \left (f (a+b x)^p (c+d x)^q\right )^r\right ) \, dx=-\frac {3 \, {\left (b^{4} d^{4} h^{3} p + b^{4} d^{4} h^{3} q\right )} r x^{4} + 4 \, {\left ({\left (4 \, b^{4} d^{4} g h^{2} - a b^{3} d^{4} h^{3}\right )} p + {\left (4 \, b^{4} d^{4} g h^{2} - b^{4} c d^{3} h^{3}\right )} q\right )} r x^{3} + 6 \, {\left ({\left (6 \, b^{4} d^{4} g^{2} h - 4 \, a b^{3} d^{4} g h^{2} + a^{2} b^{2} d^{4} h^{3}\right )} p + {\left (6 \, b^{4} d^{4} g^{2} h - 4 \, b^{4} c d^{3} g h^{2} + b^{4} c^{2} d^{2} h^{3}\right )} q\right )} r x^{2} + 12 \, {\left ({\left (4 \, b^{4} d^{4} g^{3} - 6 \, a b^{3} d^{4} g^{2} h + 4 \, a^{2} b^{2} d^{4} g h^{2} - a^{3} b d^{4} h^{3}\right )} p + {\left (4 \, b^{4} d^{4} g^{3} - 6 \, b^{4} c d^{3} g^{2} h + 4 \, b^{4} c^{2} d^{2} g h^{2} - b^{4} c^{3} d h^{3}\right )} q\right )} r x - 12 \, {\left (b^{4} d^{4} h^{3} p r x^{4} + 4 \, b^{4} d^{4} g h^{2} p r x^{3} + 6 \, b^{4} d^{4} g^{2} h p r x^{2} + 4 \, b^{4} d^{4} g^{3} p r x + {\left (4 \, a b^{3} d^{4} g^{3} - 6 \, a^{2} b^{2} d^{4} g^{2} h + 4 \, a^{3} b d^{4} g h^{2} - a^{4} d^{4} h^{3}\right )} p r\right )} \log \left (b x + a\right ) - 12 \, {\left (b^{4} d^{4} h^{3} q r x^{4} + 4 \, b^{4} d^{4} g h^{2} q r x^{3} + 6 \, b^{4} d^{4} g^{2} h q r x^{2} + 4 \, b^{4} d^{4} g^{3} q r x + {\left (4 \, b^{4} c d^{3} g^{3} - 6 \, b^{4} c^{2} d^{2} g^{2} h + 4 \, b^{4} c^{3} d g h^{2} - b^{4} c^{4} h^{3}\right )} q r\right )} \log \left (d x + c\right ) - 12 \, {\left (b^{4} d^{4} h^{3} x^{4} + 4 \, b^{4} d^{4} g h^{2} x^{3} + 6 \, b^{4} d^{4} g^{2} h x^{2} + 4 \, b^{4} d^{4} g^{3} x\right )} \log \left (e\right ) - 12 \, {\left (b^{4} d^{4} h^{3} r x^{4} + 4 \, b^{4} d^{4} g h^{2} r x^{3} + 6 \, b^{4} d^{4} g^{2} h r x^{2} + 4 \, b^{4} d^{4} g^{3} r x\right )} \log \left (f\right )}{48 \, b^{4} d^{4}} \]
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Timed out. \[ \int (g+h x)^3 \log \left (e \left (f (a+b x)^p (c+d x)^q\right )^r\right ) \, dx=\text {Timed out} \]
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Time = 0.20 (sec) , antiderivative size = 431, normalized size of antiderivative = 1.56 \[ \int (g+h x)^3 \log \left (e \left (f (a+b x)^p (c+d x)^q\right )^r\right ) \, dx=\frac {1}{4} \, {\left (h^{3} x^{4} + 4 \, g h^{2} x^{3} + 6 \, g^{2} h x^{2} + 4 \, g^{3} x\right )} \log \left (\left ({\left (b x + a\right )}^{p} {\left (d x + c\right )}^{q} f\right )^{r} e\right ) + \frac {r {\left (\frac {12 \, {\left (4 \, a b^{3} f g^{3} p - 6 \, a^{2} b^{2} f g^{2} h p + 4 \, a^{3} b f g h^{2} p - a^{4} f h^{3} p\right )} \log \left (b x + a\right )}{b^{4}} + \frac {12 \, {\left (4 \, c d^{3} f g^{3} q - 6 \, c^{2} d^{2} f g^{2} h q + 4 \, c^{3} d f g h^{2} q - c^{4} f h^{3} q\right )} \log \left (d x + c\right )}{d^{4}} - \frac {3 \, b^{3} d^{3} f h^{3} {\left (p + q\right )} x^{4} - 4 \, {\left (a b^{2} d^{3} f h^{3} p - {\left (4 \, d^{3} f g h^{2} {\left (p + q\right )} - c d^{2} f h^{3} q\right )} b^{3}\right )} x^{3} - 6 \, {\left (4 \, a b^{2} d^{3} f g h^{2} p - a^{2} b d^{3} f h^{3} p - {\left (6 \, d^{3} f g^{2} h {\left (p + q\right )} - 4 \, c d^{2} f g h^{2} q + c^{2} d f h^{3} q\right )} b^{3}\right )} x^{2} - 12 \, {\left (6 \, a b^{2} d^{3} f g^{2} h p - 4 \, a^{2} b d^{3} f g h^{2} p + a^{3} d^{3} f h^{3} p - {\left (4 \, d^{3} f g^{3} {\left (p + q\right )} - 6 \, c d^{2} f g^{2} h q + 4 \, c^{2} d f g h^{2} q - c^{3} f h^{3} q\right )} b^{3}\right )} x}{b^{3} d^{3}}\right )}}{48 \, f} \]
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Timed out. \[ \int (g+h x)^3 \log \left (e \left (f (a+b x)^p (c+d x)^q\right )^r\right ) \, dx=\text {Timed out} \]
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Time = 1.88 (sec) , antiderivative size = 641, normalized size of antiderivative = 2.32 \[ \int (g+h x)^3 \log \left (e \left (f (a+b x)^p (c+d x)^q\right )^r\right ) \, dx=\ln \left (e\,{\left (f\,{\left (a+b\,x\right )}^p\,{\left (c+d\,x\right )}^q\right )}^r\right )\,\left (g^3\,x+\frac {3\,g^2\,h\,x^2}{2}+g\,h^2\,x^3+\frac {h^3\,x^4}{4}\right )-x\,\left (\frac {\left (4\,a\,d+4\,b\,c\right )\,\left (\frac {\left (4\,a\,d+4\,b\,c\right )\,\left (\frac {h^2\,r\,\left (b\,c\,h\,p+4\,b\,d\,g\,p+a\,d\,h\,q+4\,b\,d\,g\,q\right )}{4\,b\,d}-\frac {h^3\,r\,\left (p+q\right )\,\left (4\,a\,d+4\,b\,c\right )}{16\,b\,d}\right )}{4\,b\,d}-\frac {g\,h\,r\,\left (2\,b\,c\,h\,p+3\,b\,d\,g\,p+2\,a\,d\,h\,q+3\,b\,d\,g\,q\right )}{2\,b\,d}+\frac {a\,c\,h^3\,r\,\left (p+q\right )}{4\,b\,d}\right )}{4\,b\,d}+\frac {g^2\,r\,\left (3\,b\,c\,h\,p+2\,b\,d\,g\,p+3\,a\,d\,h\,q+2\,b\,d\,g\,q\right )}{2\,b\,d}-\frac {a\,c\,\left (\frac {h^2\,r\,\left (b\,c\,h\,p+4\,b\,d\,g\,p+a\,d\,h\,q+4\,b\,d\,g\,q\right )}{4\,b\,d}-\frac {h^3\,r\,\left (p+q\right )\,\left (4\,a\,d+4\,b\,c\right )}{16\,b\,d}\right )}{b\,d}\right )-x^3\,\left (\frac {h^2\,r\,\left (b\,c\,h\,p+4\,b\,d\,g\,p+a\,d\,h\,q+4\,b\,d\,g\,q\right )}{12\,b\,d}-\frac {h^3\,r\,\left (p+q\right )\,\left (4\,a\,d+4\,b\,c\right )}{48\,b\,d}\right )+x^2\,\left (\frac {\left (4\,a\,d+4\,b\,c\right )\,\left (\frac {h^2\,r\,\left (b\,c\,h\,p+4\,b\,d\,g\,p+a\,d\,h\,q+4\,b\,d\,g\,q\right )}{4\,b\,d}-\frac {h^3\,r\,\left (p+q\right )\,\left (4\,a\,d+4\,b\,c\right )}{16\,b\,d}\right )}{8\,b\,d}-\frac {g\,h\,r\,\left (2\,b\,c\,h\,p+3\,b\,d\,g\,p+2\,a\,d\,h\,q+3\,b\,d\,g\,q\right )}{4\,b\,d}+\frac {a\,c\,h^3\,r\,\left (p+q\right )}{8\,b\,d}\right )-\frac {\ln \left (a+b\,x\right )\,\left (p\,r\,a^4\,h^3-4\,p\,r\,a^3\,b\,g\,h^2+6\,p\,r\,a^2\,b^2\,g^2\,h-4\,p\,r\,a\,b^3\,g^3\right )}{4\,b^4}-\frac {\ln \left (c+d\,x\right )\,\left (q\,r\,c^4\,h^3-4\,q\,r\,c^3\,d\,g\,h^2+6\,q\,r\,c^2\,d^2\,g^2\,h-4\,q\,r\,c\,d^3\,g^3\right )}{4\,d^4}-\frac {h^3\,r\,x^4\,\left (p+q\right )}{16} \]
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